Message 256404 - Python tracker

> The frozenset are different are expected.

Oh wait, in this example, it works, but not because of the expected reason. frozenset({1}) is equal to frozenset({1.0}) and code_richcompare() doesn't create a special key to make them different.

The example only works because the peephole optimizer is lazy and leave 1 and 1.0 in co_consts which are seen as different by the patched code_richcompare().