Message 349578 - Python tracker

Batuhan, unfortunately your second solution does not work too, because continue and break can be conditional. For example:

def simple(x):
    for number in range(2):
        try:
            return number
        finally:
            if x:
                continue

print(simple(0))
print(simple(1))

It should print:

0
None


Ethan, your understanding is correct.