std::complex<T>::imag - cppreference.com
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| primary template |
||
T imag() const; |
(1) | (until C++14) |
constexpr T imag() const; |
(since C++14) | |
void imag( T value ); |
(2) | (until C++20) |
constexpr void imag( T value ); |
(since C++20) | |
| specialization |
||
float imag() const; |
(1) | (until C++11) |
constexpr float imag() const; |
(since C++11) | |
void imag( float value ); |
(2) | (until C++20) |
constexpr void imag( float value ); |
(since C++20) | |
| specialization |
||
double imag() const; |
(1) | (until C++11) |
constexpr double imag() const; |
(since C++11) | |
void imag( double value ); |
(2) | (until C++20) |
constexpr void imag( double value ); |
(since C++20) | |
| specialization |
||
long double imag() const; |
(1) | (until C++11) |
constexpr long double imag() const; |
(since C++11) | |
void imag( long double value ); |
(2) | (until C++20) |
constexpr void imag( long double value ); |
(since C++20) | |
Accesses the imaginary part of the complex number.
1) Returns the imaginary part.
2) Sets the imaginary part to value.
Parameters
| value | - | the value to set the imaginary part to |
Return value
1) The imaginary part of *this.
2) (none)
Notes
In C++11, overload (1) in std::complex specializations used to be specified without const qualifier. However, in C++11, a constexpr specifier used in a non-static member function implies const, and thus the behavior is as if const is specified.
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 387 | C++98 | the imaginary part could not be set directly | can be set directly via a new imag overload
|
See also
| returns the imaginary part (function template) [edit] | |
| accesses the real part of the complex number (public member function) [edit] |