std::merge – cppreference.com
Aus cppreference.com
<metanoindex/>
<tbody> </tbody>
| definiert in Header <algorithm> |
||
|
|
(1) | |
|
|
(2) | |
Führt zwei sortierten Bereiche [first1, last1) und [first2, last2) in einem sortierten Bereich beginnend bei d_first. Die erste Version verwendet operator< um die Elemente zu vergleichen, verwendet die zweite Version des gegebenen Vergleichsfunktion comp. Die relative Reihenfolge gleicher Elemente erhalten .
Original:
Merges two sorted ranges [first1, last1) and [first2, last2) into one sorted range beginning at d_first. The first version uses operator< to compare the elements, the second version uses the given comparison function comp. The relative order of equivalent elements is preserved.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Parameter
| first1, last1 | - | die erste Reihe von Elementen zu fusionieren Original: the first range of elements to merge The text has been machine-translated via Google Translate. |
| first2, last2 | - | der zweite Bereich von Elementen zu fusionieren Original: the second range of elements to merge The text has been machine-translated via Google Translate. |
| d_first | - | der Beginn des Zielbereichs Original: the beginning of the destination range The text has been machine-translated via Google Translate. |
| comp | - | comparison function which returns true if the first argument is less than the second.
The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1 must meet the requirements of InputIterator.
| ||
-InputIt2 must meet the requirements of InputIterator.
| ||
-OutputIt must meet the requirements of OutputIterator.
| ||
Rückgabewert
Ein Ausgang Iterator auf das Element nach dem letzten Element kopiert .
Original:
An output iterator to element past the last element copied.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Komplexität
An den meisten std::distance(first1, last1) + std::distance(first2, last2) + 1 Vergleiche .
Original:
At most std::distance(first1, last1) + std::distance(first2, last2) + 1 comparisons.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Mögliche Implementierung
| First version |
|---|
template<class InputIt1, class InputIt2, class OutputIt> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first) { for (; first1 != last1; ++d_first) { if (first2 == last2) { return std::copy(first1, last1, d_first); } if (*first2 < *first1) { *d_first = *first2; ++first2; } else { *d_first = *first1; ++first1; } } return std::copy(first2, last2, d_first); } |
| Second version |
template<class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp) { for (; first1 != last1; ++d_first) { if (first2 == last2) { return std::copy(first1, last1, d_first); } if (comp(*first2, *first1)) { *d_first = *first2; ++first2; } else { *d_first = *first1; ++first1; } } return std::copy(first2, last2, d_first); } |
Beispiel
#include <iostream> #include <iterator> #include <cstdlib> #include <algorithm> #include <vector> int main() { const std::size_t items = 10; std::vector<int> v1, v2, dst; // fill the vectors for (std::size_t idx = 0; idx < items; ++idx) { v1.push_back(std::rand()%items); v2.push_back(std::rand()%items); } // sort std::sort(v1.begin(), v1.end()); std::sort(v2.begin(), v2.end()); // output v1 std::cout << "v1 : "; std::copy(v1.begin(), v1.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; // output v2 std::cout << "v2 : "; std::copy(v2.begin(), v2.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; // merge std::merge(v1.begin(), v1.end(), v2.begin(), v2.end(), std::back_inserter(dst)); // output std::cout << "dst: "; std::copy(dst.begin(), dst.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Output:
v1 : 0 0 2 2 3 3 3 6 7 9 v2 : 1 2 5 5 6 6 6 6 7 9 dst: 0 0 1 2 2 2 3 3 3 5 5 6 6 6 6 6 7 7 9 9
Siehe auch
führt zwei bestellt reicht in-place Original: merges two ordered ranges in-place The text has been machine-translated via Google Translate. (Funktions-Template) [edit] | |
Sortiert einen Bereich in aufsteigender Reihenfolge Original: sorts a range into ascending order The text has been machine-translated via Google Translate. (Funktions-Template) [edit] | |
Arten eine Reihe von Elementen, während Aufrechterhaltung der Ordnung zwischen gleichen Elementen Original: sorts a range of elements while preserving order between equal elements The text has been machine-translated via Google Translate. (Funktions-Template) [edit] | |