std::list::remove, std::list::remove_if – cppreference.com

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`void remove( const T& value );`

`template< class UnaryPredicate > void remove_if( UnaryPredicate p );`

Entfernt alle Elemente, die die spezifischen Kriterien. Die erste Version entfernt alle Elemente, die gleich value sind, entfernt der zweiten Version, für die alle Elemente Prädikats p kehrt true .

Original:

Removes all elements satisfying specific criteria. The first version removes all elements that are equal to value, the second version removes all elements for which predicate p returns true.

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Parameter

value

Wert der Elemente zu entfernen

Original:

value of the elements to remove

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unary predicate which returns true

wenn das Element entfernt werden sollte

Original:

if the element should be removed

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The signature of the predicate function should be equivalent to the following:

bool pred(const Type &a);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The type Type must be such that an object of type list<T,Allocator>::const_iterator can be dereferenced and then implicitly converted to Type.

Rückgabewert

(None)

Original:

(none)

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Komplexität

linear in der Größe des Behälters

Original:

linear in the size of the container

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Beispiel

#include <list>
#include <iostream>

int main()
{
    std::list<int> l = { 1,100,2,3,10,1,11,-1,12 };

    l.remove(1); // remove both elements equal to 1
    l.remove_if([](int n){ return n > 10; }); // remove all elements greater than 10

    for (int n : l) {
        std::cout << n << ' '; 
    }
    std::cout << '\n';
}

Output:

Siehe auch


	Entfernt Elemente erfüllen bestimmte Kriterien Original: removes elements satisfying specific criteria The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (Funktions-Template) [edit]