std::next – cppreference.com
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(seit C++11) | |
Bringen Sie den nth Nachfolger von Iterator it .
Original:
Return the nth successor of iterator it.
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Parameter
| it | - | ein iterater ' Original: an iterater' The text has been machine-translated via Google Translate. |
| n | - | Anzahl der Elemente, um fortzufahren Original: number of elements to advance The text has been machine-translated via Google Translate. |
| Type requirements | ||
-ForwardIt must meet the requirements of ForwardIterator.
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Rückgabewert
Die nth Nachfolger von Iterator it .
Original:
The nth successor of iterator it.
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You can help to correct and verify the translation. Click here for instructions.
Mögliche Implementierung
template<class ForwardIt> ForwardIt next(ForwardIt it, typename std::iterator_traits<ForwardIt>::difference_type n = 1) { std::advance(it, n); return it; }
Beispiel
#include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> v{ 3, 1, 4 }; auto it = v.begin(); auto nx = std::next(it, 2); std::cout << *it << ' ' << *nx << '\n'; }
Output:
Siehe auch
dekrementieren einen Iterator Original: decrement an iterator The text has been machine-translated via Google Translate. (Funktion) [edit] | |
Fortschritte einen Iterator gegeben durch Distanz Original: advances an iterator by given distance The text has been machine-translated via Google Translate. (Funktion) [edit] | |