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std::has_virtual_destructor – cppreference.com

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definiert in Header

<type_traits>

template< class T > struct has_virtual_destructor;

 (seit C++11)

Wenn T ein Typ mit einem virtuellen Destruktor ist, stellt das Mitglied konstanten value gleich true. Für jede andere Art, value ist false .

Original:

If T is a type with a virtual destructor, provides the member constant value equal true. For any other type, value is false.

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Inherited from std::integral_constant

Member constants

true wenn T has a virtual destructor , false anders

Original:

true if T has a virtual destructor , false otherwise

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(public static Mitglied konstanten)

Member functions

wandelt das Objekt bool, gibt value

Original:

converts the object to bool, returns value

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(öffentliche Elementfunktion)

Member types

Type

Original:

Type

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 Definition
value_type bool
type std::integral_constant<bool, value>

Notes

Wenn eine Klasse eine öffentliche virtuelle destructor, kann es aus abgeleitet werden, und der abgeleitet Objekt kann sicher durch einen Zeiger werden auf das Basisobjekt (C++FAQ Lite 20.7) gelöscht

Original:

If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (C++FAQ Lite 20.7)

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Beispiel

#include <iostream>
#include <type_traits>
#include <string>
#include <stdexcept>

int main()
{
    std::cout << std::boolalpha
              << "std::string has a virtual destructor? "
              << std::has_virtual_destructor<std::string>::value << '\n'
              << "std::runtime_error has a virtual destructor? "
              << std::has_virtual_destructor<std::runtime_error>::value << '\n';
}

Output: 

std::string has a virtual destructor? false
std::runtime_error has a virtual destructor? true

Siehe auch