std::is_constructible, std::is_trivially_constructible, std::is_nothrow_constructible – cppreference.com
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(1) | (seit C++11) |
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(2) | (seit C++11) |
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(3) | (seit C++11) |
1)
Wenn der Ausdruck T obj(arg1, arg2, ... argN); ist wohlgeformt, da rvalue Verweise auf Args... als Argumente, bietet das Mitglied konstanten value gleich true. Für jede andere Art, value ist false .
Original:
If the expression T obj(arg1, arg2, ... argN); is well-formed, given rvalue references to Args... as arguments, provides the member constant value equal true. For any other type, value is false.
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2)
wie 1), aber der Konstruktor Ausdruck nicht nennen jede Operation, die nicht trivial ist .
Original:
same as 1), but the constructor expression does not call any operation that is not trivial.
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3)
Gleiche wie 1), aber der Konstruktor Expression noexcept .
Original:
same as 1), but the constructor expression is noexcept.
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Inherited from std::integral_constant
Member constants
Original:
The text has been machine-translated via Google Translate. (public static Mitglied konstanten) | |
Member functions
wandelt das Objekt Original: converts the object to The text has been machine-translated via Google Translate. (öffentliche Elementfunktion) | |
Member types
Type Original: Type The text has been machine-translated via Google Translate. |
Definition |
value_type
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bool
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type
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std::integral_constant<bool, value>
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Beispiel
#include <iostream> #include <type_traits> class Foo { int v1; double v2; public: Foo(int n) : v1(n), v2() {} Foo(int n, double f) noexcept : v1(n), v2(f) {} }; int main() { std::cout << "Foo is ...\n" << std::boolalpha << "\tTrivially-constructible from const Foo&? " << std::is_trivially_constructible<Foo, const Foo&>::value << '\n' << "\tTrivially-constructible from int? " << std::is_trivially_constructible<Foo, int>::value << '\n' << "\tConstructible from int? " << std::is_constructible<Foo, int>::value << '\n' << "\tNothrow-constructible from int? " << std::is_nothrow_constructible<Foo, int>::value << '\n' << "\tNothrow-constructible from int and double? " << std::is_nothrow_constructible<Foo, int, double>::value << '\n'; }
Output:
Foo is ...
Trivially-constructible from const Foo&? true
Trivially-constructible from int? false
Constructible from int? true
Nothrow-constructible from int? false
Nothrow-constructible from int and double? true
Siehe auch
prüft, ob ein Typ hat einen Default-Konstruktor Original: checks if a type has a default constructor The text has been machine-translated via Google Translate. (Klassen-Template) [edit] | |
(C++11) |
prüft, ob ein Typ hat einen Copy-Konstruktor Original: checks if a type has a copy constructor The text has been machine-translated via Google Translate. (Klassen-Template) [edit] |
(C++11) |
prüft, ob ein Typ hat einen Umzug Konstruktor Original: checks if a type has a move constructor The text has been machine-translated via Google Translate. (Klassen-Template) [edit] |
(C++11) |
prüft, ob der angegebene Typ allokatorgestützte Erzeugung unterstützt. (Klassen-Template) [edit] |