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std::remove_copy, std::remove_copy_if — cppreference.com

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Déclaré dans l'en-tête

<algorithm>

template< class InputIt, class OutputIt, class T > OutputIt remove_copy( InputIt first, InputIt last, OutputIt d_first, const T& value );

(1)

template< class InputIt, class OutputIt, class UnaryPredicate > OutputIt remove_copy_if( InputIt first, InputIt last, OutputIt d_first, UnaryPredicate p );

(2)

Copie les éléments de la gamme [first, last), à une autre gamme débutant à d_first, en omettant les éléments qui satisfont à des critères spécifiques. La première version ne tient pas compte des éléments qui sont égaux à value, la deuxième version ne tient pas compte des éléments pour lesquels prédicat retourne p true. Gammes de source et de destination ne peuvent pas se chevaucher .

Original:

Copies elements from the range [first, last), to another range beginning at d_first, omitting the elements which satisfy specific criteria. The first version ignores the elements that are equal to value, the second version ignores the elements for which predicate p returns true. Source and destination ranges cannot overlap.

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Paramètres

first, last -

l'éventail des éléments à copier

Original:

the range of elements to copy

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d_first -

le début de la plage de destination .

Original:

the beginning of the destination range.

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value -

la valeur des éléments non copier

Original:

the value of the elements not to copy

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Type requirements
-InputIt must meet the requirements of InputIterator.
-OutputIt must meet the requirements of OutputIterator.

Retourne la valeur

Itérateur à l'élément après le dernier élément copié .

Original:

Iterator to the element past the last element copied.

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Complexité

Exactement last - first applications du prédicat .

Original:

Exactly last - first applications of the predicate.

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Mise en œuvre possible

First version
template<class InputIt, class OutputIt, class T>
OutputIt remove_copy(InputIt first, InputIt last,
                     OutputIt d_first, const T& value)
{
    for (; first != last; ++first) {
        if (!(*first == value)) {
            *d_first++ = *first;
        }
    }
    return d_first;
}
Second version
template<class InputIt, class OutputIt, class UnaryPredicate>
OutputIt remove_copy_if(InputIt first, InputIt last,
                        OutputIt d_first, UnaryPredicate p)
{
    for (; first != last; ++first) {
        if (!p(*first)) {
            *d_first++ = *first;
        }
    }
    return d_first;
}

Exemple

Le code suivant génère une chaîne tout en effaçant les espaces à la volée .

Original:

The following code outputs a string while erasing the spaces on the fly.

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#include <algorithm>
#include <iterator>
#include <string>
#include <iostream>
int main()
{
    std::string str = "Text with some   spaces";
    std::cout << "before: " << str << "\n";

    std::cout << "after:  ";
    std::remove_copy(str.begin(), str.end(),
                     std::ostream_iterator<char>(std::cout), ' ');
    std::cout << '\n';
}

Résultat :

before: Text with some   spaces
after:  Textwithsomespaces

Voir aussi

supprime des éléments répondant à des critères spécifiques

Original:

removes elements satisfying specific criteria

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(fonction générique) [edit]