std::replace, std::replace_if — cppreference.com
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| Déclaré dans l'en-tête <algorithm> |
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Remplace tous les éléments répondant à des critères spécifiques new_value dans le [first, last) gamme. La première version remplace les éléments qui sont égaux à old_value, la deuxième version remplace les éléments pour lesquels prédicat retourne p true .
Original:
Replaces all elements satisfying specific criteria with new_value in the range [first, last). The first version replaces the elements that are equal to old_value, the second version replaces elements for which predicate p returns true.
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Paramètres
| first, last | - | l'ensemble d'éléments de processus Original: the range of elements to process The text has been machine-translated via Google Translate. |
| old_value | - | la valeur des éléments à remplacer Original: the value of elements to replace The text has been machine-translated via Google Translate. |
| p | - | prédicat unéaire qui retourne true si la valeur de l'élément doit être remplacé Original: if the element value should be replaced The text has been machine-translated via Google Translate. L'expression |
| new_value | - | la valeur à utiliser en remplacement Original: the value to use as replacement The text has been machine-translated via Google Translate. |
| Type requirements | ||
-ForwardIt must meet the requirements of ForwardIterator.
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Retourne la valeur
(Aucun)
Original:
(none)
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Complexité
Exactement last - first applications du prédicat .
Original:
Exactly last - first applications of the predicate.
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Mise en œuvre possible
| First version |
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template<class ForwardIt, class T> void replace(ForwardIt first, ForwardIt last, const T& old_value, const T& new_value) { for (; first != last; ++first) { if (*first == old_value) { *first = new_value; } } } |
| Second version |
template<class ForwardIt, class UnaryPredicate, class T> void replace_if(ForwardIt first, ForwardIt last, UnaryPredicate p, const T& new_value) { for (; first != last; ++first) { if(p(*first)) { *first = new_value; } } } |
Exemple
Le code suivant au début remplace toutes les occurrences de 8 avec 88 dans un vecteur d'entiers. Puis il remplace toutes les valeurs inférieures à 55 .. 5
Original:
The following code at first replaces all occurrences of 8 with 88 in a vector of integers. Then it replaces all values less than 5 with 55.
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#include <algorithm> #include <array> #include <iostream> #include <functional> int main() { std::array<int, 10> s{5, 7, 4, 2, 8, 6, 1, 9, 0, 3}; std::replace(s.begin(), s.end(), 8, 88); for (int a : s) { std::cout << a << " "; } std::cout << '\n'; std::replace_if(s.begin(), s.end(), std::bind(std::less<int>(), std::placeholders::_1, 5), 55); for (int a : s) { std::cout << a << " "; } std::cout << '\n'; }
Résultat :
5 7 4 2 88 6 1 9 0 3 5 7 55 55 99 6 55 9 55 55
Voir aussi
copie d'une plage, le remplacement des éléments satisfaisant à des critères spécifiques à une autre valeur Original: copies a range, replacing elements satisfying specific criteria with another value The text has been machine-translated via Google Translate. (fonction générique) [edit] | |