noexcept specifier (depuis C++11) — cppreference.com

<metanoindex/>

Specifies whether a function will throw exceptions or not.

Syntaxe

Explication

If the value of the constant expression is true, the function is declared to not throw any exceptions. noexcept without a constant expression is equivalent to noexcept(true).

One of the uses of the constant expression is (along with the NJ opérateur) to define templated functions that declare noexcept for some types but not others.

Note that a noexcept specification on a function is not a compile-time check; it is merely a method for a programmer to inform the compiler whether or not a function should throw exceptions. The compiler can use this information to enable certain optimizations on non-throwing functions as well as enable the NJ opérateur, which can check at compile time if a particular expression is declared to throw any exceptions. For example, containers such as std::vector will move their elements if the elements' move constructor is noexcept, and copy otherwise.

If a function marked noexcept allows an uncaught exception to escape at runtime, std::terminate is called immediately.

Deprecates

noexcept is an improved version of throw(), which is deprecated in C++11. Unlike throw(), noexcept will not call std::unexpected and may or may not unwind the stack, which potentially allows the compiler to implement noexcept without the runtime overhead of throw().

Mots-clés

noexcept

Exemple

// whether foo is declared noexcept depends on if the expression
// T() will throw any exceptions
template <class T>
  void foo() noexcept(noexcept(T())) {}
void bar() noexcept(true) {}
void baz() noexcept { throw 42; }  // noexcept is the same as noexcept(true)

int main() 
{
    foo<int>();  // noexcept(noexcept(int())) => noexcept(true), so this is fine

    bar();  // fine
    baz();  // compiles, but at runtime this calls std::terminate
}

Voir aussi