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std::has_virtual_destructor — cppreference.com

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Déclaré dans l'en-tête

<type_traits>

template< class T > struct has_virtual_destructor;

 (depuis C++11)

Si T est un type avec un destructeur virtuel, fournit du membre de constante value true égale. Pour tout autre type, value est false .

Original:

If T is a type with a virtual destructor, provides the member constant value equal true. For any other type, value is false.

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Inherited from std::integral_constant

Member constants

value

[

statique

Original:

static

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]

true si T has a virtual destructor , false autrement

Original:

true if T has a virtual destructor , false otherwise

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(constante membre statique publique)

Member functions

convertit l'objet en bool, retourne value

Original:

converts the object to bool, returns value

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(fonction membre publique)

Member types

Type d'

Original:

Type

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 Definition
value_type bool
type std::integral_constant<bool, value>

Notes

Si une classe a un destructeur virtuel public, il peut être dérivé, et l'objet dérivé peut être supprimé en toute sécurité grâce à un pointeur sur l'objet de base (C++FAQ Lite 20.7)

Original:

If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (C++FAQ Lite 20.7)

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Exemple

#include <iostream>
#include <type_traits>
#include <string>
#include <stdexcept>

int main()
{
    std::cout << std::boolalpha
              << "std::string has a virtual destructor? "
              << std::has_virtual_destructor<std::string>::value << '\n'
              << "std::runtime_error has a virtual destructor? "
              << std::has_virtual_destructor<std::runtime_error>::value << '\n';
}

Résultat : 

std::string has a virtual destructor? false
std::runtime_error has a virtual destructor? true

Voir aussi