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std::find_end - cppreference.com

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Elemento definito nell'header

<algorithm>

template< class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last );

(1)

template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p );

(2)

Cerca la sottosequenza ultimo [s_first, s_last) elementi nel [first, last) gamma. La prima versione utilizza operator== di confrontare gli elementi, la seconda versione utilizza il predicato binario dato p.

Original:

Searches for the last subsequence of elements [s_first, s_last) in the range [first, last). The first version uses operator== to compare the elements, the second version uses the given binary predicate p.

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Parametri

first, last -

la gamma di elementi da esaminare

Original:

the range of elements to examine

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s_first, s_last -

la gamma di elementi da cercare

Original:

the range of elements to search for

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p - binary predicate which returns ​true if the elements should be treated as equal.

The signature of the predicate function should be equivalent to the following:

bool pred(const Type1 &a, const Type2 &b);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The types Type1 and Type2 must be such that objects of types ForwardIt1 and ForwardIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively.

Type requirements
-ForwardIt1 must meet the requirements of ForwardIterator.
-ForwardIt2 must meet the requirements of ForwardIterator.

Valore di ritorno

Iterator all'inizio [s_first, s_last) sottosuccessione ultima gamma [first, last).

Original:

Iterator to the beginning of last subsequence [s_first, s_last) in range [first, last).

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Se non sottosequenza non viene trovato, viene restituito last. (fino al c++11)

Original:

If no such subsequence is found, last is returned. (fino al c++11)

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Se [s_first, s_last) è vuoto o se non sottosequenza non viene trovato, viene restituito last. (dal C++11)

Original:

If [s_first, s_last) is empty or if no such subsequence is found, last is returned. (dal C++11)

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Complessità

Fa a confronto la maggior parte S*(N-S+1) dove S = distance(s_first, s_last) e N = distance(first, last).

Original:

Does at most S*(N-S+1) comparisons where S = distance(s_first, s_last) and N = distance(first, last).

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Possibile implementazione

First version
template<class ForwardIt1, class ForwardIt2>
ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last,
                    ForwardIt2 s_first, ForwardIt2 s_last)
{
    if (s_first == s_last)
        return last;
    ForwardIt1 result = last;
    while (1) {
        ForwardIt1 new_result = std::search(first, last, s_first, s_last);
        if (new_result == last) {
            return result;
        } else {
            result = new_result;
            first = result;
            ++first;
        }
    }
    return result;
}
Second version
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate>
ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last,
                    ForwardIt2 s_first, ForwardIt2 s_last,
                    BinaryPredicate p)
{
    if (s_first == s_last)
        return last;
    ForwardIt1 result = last;
    while (1) {
        ForwardIt1 new_result = std::search(first, last, s_first, s_last, p);
        if (new_result == last) {
            return result;
        } else {
            result = new_result;
            first = result;
            ++first;
        }
    }
    return result;
}

Esempio

Il codice seguente utilizza find_end() per la ricerca di due diverse sequenze di numeri .

Original:

The following code uses find_end() to search for two different sequences of numbers.

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#include <algorithm>
#include <iostream>
#include <vector>

int main()
{
    std::vector<int> v{1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4};
    std::vector<int>::iterator result;
 
    std::vector<int> t1{1, 2, 3};

    result = std::find_end(v.begin(), v.end(), t1.begin(), t1.end());
    if (result == v.end()) {
        std::cout << "subsequence not found\n";
    } else {
        std::cout << "last subsequence is at: "
                  << std::distance(v.begin(), result) << "\n";
    }

    std::vector<int> t2{4, 5, 6};
    result = std::find_end(v.begin(), v.end(), t2.begin(), t2.end());
    if (result == v.end()) {
        std::cout << "subsequence not found\n";
    } else {
        std::cout << "last subsequence is at: " 
                  << std::distance(v.begin(), result) << "\n";
    }
}

Output:

last subsequence is at: 8
subsequence not found

Vedi anche

trova due identici (o qualche altra relazione) elementi adiacenti l'uno all'altro

Original:

finds two identical (or some other relationship) items adjacent to each other

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(funzione di modello) [modifica]

trova il primo elemento che soddisfi i criteri specifici

Original:

finds the first element satisfying specific criteria

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(funzione di modello) [modifica]
searches for any one of a set of elements
(funzione di modello) [modifica]

ricerche di un numero di copie consecutive di un elemento in un intervallo

Original:

searches for a number consecutive copies of an element in a range

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(funzione di modello) [modifica]