std::adjacent_difference - cppreference.com
De cppreference.com
<metanoindex/>
<tbody> </tbody>
| Definido no cabeçalho <numeric> |
||
|
|
(1) | |
|
|
(2) | |
Calcula as diferenças entre a segunda e a primeira de cada par adjacente de elementos da gama [first, last) e grava-os da gama de d_first + 1. Cópia sem modificações de first é escrito para d_first. A primeira versão utiliza operator- para calcular as diferenças, a segunda versão utiliza a função binária dada op.
Original:
Computes the differences between the second and the first of each adjacent pair of elements of the range [first, last) and writes them to the range beginning at d_first + 1. Unmodified copy of first is written to d_first. The first version uses operator- to calculate the differences, the second version uses the given binary function op.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Operação equivalente:
Original:
Equivalent operation:
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
*(d_first) = *first; *(d_first+1) = (*first+1) - *(first); *(d_first+2) = (*first+2) - *(first+1); *(d_first+3) = (*first+3) - *(first+2); ...
Parâmetros
| first, last | - | o intervalo de elementos Original: the range of elements The text has been machine-translated via Google Translate. |
| d_first | - | o início do intervalo de destino Original: the beginning of the destination range The text has been machine-translated via Google Translate. |
| op | - | binary operation function object that will be applied.
The signature of the function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt must meet the requirements of InputIterator.
| ||
-OutputIt must meet the requirements of OutputIterator.
| ||
Valor de retorno
Ao elemento passado o último elemento escrito.
Original:
It to the element past the last element written.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Complexidade
Exatamente (last - first) - 1 aplicações da operação binária
Original:
Exactly (last - first) - 1 applications of the binary operation
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Possível implementação
| First version |
|---|
template<class InputIt, class OutputIt> OutputIt adjacent_difference(InputIt first, InputIt last, OutputIt d_first) { if (first == last) return d_first; typedef typename std::iterator_traits<InputIt>::value_type value_t; value_t acc = *first; *d_first = acc; while (++first != last) { value_t val = *first; *++d_first = val - acc; acc = std::move(val); } return ++d_first; } |
| Second version |
template<class InputIt, class T, class BinaryOperation> OutputIt adjacent_difference(InputIt first, InputIt last, OutputIt d_first, BinaryOperation op) { if (first == last) return d_first; typedef typename std::iterator_traits<InputIt>::value_type value_t; value_t acc = *first; *d_first = acc; while (++first != last) { value_t val = *first; *++d_first = op(val, acc); acc = std::move(val); } return ++d_first; } |
Exemplo
O código a seguir converte uma seqüência de números pares de repetições do número 2 e converte uma seqüência de uns a uma seqüência de números de Fibonacci .
Original:
The following code converts a sequence of even numbers to repetitions of the number 2 and converts a sequence of ones to a sequence of Fibonacci numbers.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
#include <numeric> #include <vector> #include <iostream> #include <functional> int main() { std::vector<int> v{2, 4, 6, 8, 10, 12, 14, 16, 18, 20}; std::adjacent_difference(v.begin(), v.end(), v.begin()); for(auto n: v) { std::cout << n << ' '; } std::cout << '\n'; v = {1, 1, 1, 1, 1, 1, 1, 1, 1, 1}; std::adjacent_difference(v.begin(), v.end()-1, v.begin()+1, std::plus<int>() for(auto n: v) { std::cout << n << ' '; } std::cout << '\n'; }
Saída:
2 2 2 2 2 2 2 2 2 2 1 1 2 3 5 8 13 21 34 55
Veja também
calcula a soma parcial de um conjunto de elementos Original: computes the partial sum of a range of elements The text has been machine-translated via Google Translate. (modelo de função) [edit] | |
resume uma série de elementos Original: sums up a range of elements The text has been machine-translated via Google Translate. (modelo de função) [edit] | |