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std::inplace_merge - cppreference.com

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Definido no cabeçalho

<algorithm>

template< class BidirIt > void inplace_merge( BidirIt first, BidirIt middle, BidirIt last );

(1)

template< class BidirIt, class Compare> void inplace_merge( BidirIt first, BidirIt middle, BidirIt last, Compare comp );

(2)

Mescla duas faixas consecutivas classificadas [first, middle) e [middle, last) em um [first, last) intervalo classificado. A ordem dos elementos iguais é garantido para ser preservado. A primeira versão utiliza operator< para comparar os elementos, a segunda versão utiliza a função de comparação dada comp.

Original:

Merges two consecutive sorted ranges [first, middle) and [middle, last) into one sorted range [first, last). The order of equal elements is guaranteed to be preserved. The first version uses operator< to compare the elements, the second version uses the given comparison function comp.

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Parâmetros

first -

o começo do primeiro intervalo de classificação

Original:

the beginning of the first sorted range

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middle -

o fim do primeiro intervalo ordenadas e o início do segundo

Original:

the end of the first sorted range and the beginning of the second

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last -

no final do segundo intervalo de classificação

Original:

the end of the second sorted range

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comp - comparison function which returns ​true if the first argument is less than the second.

The signature of the comparison function should be equivalent to the following:

bool cmp(const Type1 &a, const Type2 &b);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The types Type1 and Type2 must be such that an object of type BidirIt can be dereferenced and then implicitly converted to both of them. ​

Type requirements
-BidirIt must meet the requirements of ValueSwappable and BidirectionalIterator.
-The type of dereferenced BidirIt must meet the requirements of MoveAssignable and MoveConstructible.

Valor de retorno

(Nenhum)

Original:

(none)

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Complexidade

Exatamente N-1 comparações se a memória adicional suficiente disponível, caso contrário N·log(N) onde N = std::distance(first, last).

Original:

Exactly N-1 comparisons if enough additional memory is available, otherwise N·log(N) where N = std::distance(first, last).

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Notas

Esta função tenta alocar um buffer temporário, normalmente chamando std::get_temporary_buffer. Se a alocação falhar, o algoritmo menos eficiente é escolhido.

Original:

This function attempts to allocate a temporary buffer, typically by calling std::get_temporary_buffer. If the allocation fails, the less efficient algorithm is chosen.

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Exemplo

O código a seguir é uma implementação do merge sort .

Original:

The following code is an implementation of merge sort.

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#include <vector>
#include <iostream>
#include <algorithm>

template<class Iter>
void merge_sort(Iter first, Iter last)
{
    if (last - first > 1) {
        Iter middle = first + (last - first) / 2;
        merge_sort(first, middle);
        merge_sort(middle, last);
        std::inplace_merge(first, middle, last);
    }
}

int main()
{
    std::vector<int> v{8, 2, -2, 0, 11, 11, 1, 7, 3};
    merge_sort(v.begin(), v.end());
    for(auto n : v) {
        std::cout << n << ' ';
    }
    std::cout << '\n';
}

Saída:

Veja também

funde duas faixas de classificados

Original:

merges two sorted ranges

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(modelo de função) [edit]

tipo um intervalo em ordem crescente

Original:

sorts a range into ascending order

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(modelo de função) [edit]

Classifica um intervalo de elementos preservando ordem entre elementos iguais

Original:

sorts a range of elements while preserving order between equal elements

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(modelo de função) [edit]